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Wannafly挑战赛14
阅读量:4633 次
发布时间:2019-06-09

本文共 8167 字,大约阅读时间需要 27 分钟。

枚举推式子

1 #include 
2 using namespace std; 3 typedef long long LL; 4 LL gcd(LL a, LL b){ 5 return a % b ? gcd(b, a % b) : b; 6 } 7 int main(){ 8 int T; 9 scanf("%d", &T);10 while(T--) {11 LL K, M, six = 6;12 cin >> K >> M;13 LL a = K + 1, b = K + 2, c = K + 3;14 LL g = gcd(a, six);15 a /= g, six /= g;16 g = gcd(b, six);17 b /= g, six /= g;18 g = gcd(c, six);19 c /= g, six /= g;20 LL ans = a * b % M * c % M;21 cout << ans << endl;22 }23 return 0;24 }
Aguin

 

子树修改子树询问转路径标记

1 #include 
2 using namespace std; 3 const int maxn = 1e6 + 10; 4 typedef long long LL; 5 6 int node; 7 LL val[maxn], num[maxn], del[maxn]; 8 LL sum[maxn], tot[maxn]; 9 map
G[maxn];10 void insert(string s, LL v){11 int p = 0;12 for(int i = 0; i < s.length(); ++i){13 if(G[p].find(s[i]) == G[p].end()) G[p][s[i]] = ++node;14 p = G[p][s[i]];15 v -= del[p];16 sum[p] += v;17 tot[p]++;18 }19 val[p] += v;20 num[p]++;21 }22 void modify(string s, LL v) {23 int p = 0;24 for (int i = 0; i < s.length(); ++i) {25 if (G[p].find(s[i]) == G[p].end()) G[p][s[i]] = ++node;26 p = G[p][s[i]];27 }28 del[p] += v;29 LL tmp = tot[p];30 p = 0;31 for (int i = 0; i < s.length(); ++i) {32 if (G[p].find(s[i]) == G[p].end()) G[p][s[i]] = ++node;33 p = G[p][s[i]];34 if(i != s.length() - 1) sum[p] += tmp * v;35 }36 }37 LL Q1(string s) {38 int p = 0;39 LL tmp = 0;40 for (int i = 0; i < s.length(); ++i) {41 if (G[p].find(s[i]) == G[p].end()) G[p][s[i]] = ++node;42 p = G[p][s[i]];43 tmp += del[p];44 }45 return val[p] + tmp * num[p];46 }47 LL Q2(string s) {48 int p = 0;49 LL tmp = 0;50 for (int i = 0; i < s.length(); ++i) {51 if (G[p].find(s[i]) == G[p].end()) G[p][s[i]] = ++node;52 p = G[p][s[i]];53 tmp += del[p];54 }55 return sum[p] + tmp * tot[p];56 }57 58 char s[maxn];59 int main(){60 int N;61 scanf("%d", &N);62 for(int i = 1; i <= N; ++i){63 int o, a, b;64 scanf("%d", &o);65 if(o == 1){66 scanf("%s %d", s, &a);67 insert(string(s), a);68 }69 else if(o == 2){70 scanf("%s %d", s, &a);71 modify(string(s), a);72 }73 else if(o == 3){74 scanf("%s", s);75 printf("%lld\n", Q1(string(s)));76 }77 else{78 scanf("%s", s);79 printf("%lld\n", Q2(string(s)));80 }81 }82 return 0;83 }
Aguin

 

缩点

1 #include 
2 using namespace std; 3 const int maxn = 1e5 + 10; 4 5 // BCC 6 set
SE[maxn], ans; 7 set
:: iterator it; 8 stack
S; 9 vector
G[maxn];10 int dfs_clock, dfn[maxn], low[maxn];11 int bcc_cnt, bccno[maxn];12 void dfs(int u, int fa)13 {14 dfn[u] = low[u] = ++dfs_clock;15 S.push(u);16 for(int i = 0; i < G[u].size(); ++i)17 {18 int v = G[u][i];19 if(!dfn[v])20 {21 dfs(v, u);22 low[u] = min(low[u], low[v]);23 }24 else if(!bccno[v]) low[u] = min(low[u], dfn[v]);25 }26 27 if(low[u] == dfn[u])28 {29 bcc_cnt++;30 while(1)31 {32 int x = S.top(); S.pop();33 bccno[x] = bcc_cnt;34 SE[bcc_cnt].insert(x);35 if(x == u) break;36 }37 }38 }39 40 void find_bcc(int n)41 {42 memset(dfn, 0, sizeof(dfn));43 memset(bccno, 0, sizeof(bccno));44 dfs_clock = bcc_cnt = 0;45 for(int i = 1; i <= n; i++) if(!dfn[i]) dfs(i, 0);46 }47 48 int deg[maxn];49 int main(){50 int n, m;51 scanf("%d %d", &n, &m);52 for(int i = 1; i <= m; ++i){53 int u, v;54 scanf("%d %d", &u, &v);55 G[u].push_back(v);56 }57 find_bcc(n);58 for(int i = 1; i <= n; ++i){59 for(int j = 0; j < G[i].size(); ++j)60 if(bccno[i] != bccno[G[i][j]]) deg[bccno[G[i][j]]]++;61 }62 for(int i = 1; i <= bcc_cnt; ++i){63 if(deg[i] == 0) ans.insert(*SE[i].begin());64 }65 printf("%d\n", ans.size());66 for(it = ans.begin(); it != ans.end(); it++){67 if(it != ans.begin()) putchar(' ');68 printf("%d", *it);69 }70 puts("");71 return 0;72 }
Aguin

 

启发式合并

1 #include 
2 using namespace std; 3 const int maxn = 1e5 + 10; 4 typedef long long LL; 5 typedef pair
pii; 6 vector
G[maxn]; 7 int n, m; 8 9 int sz[maxn];10 LL bt[maxn];11 void dfs(int x, int f){12 bt[x] = 0;13 sz[x] = 1;14 for(int i = 0; i < G[x].size(); ++i){15 int to = G[x][i].first, d = G[x][i].second;16 if(to == f) continue;17 dfs(to, x);18 bt[x] += bt[to] + d * sz[to];19 sz[x] += sz[to];20 }21 }22 23 LL ans;24 int id[maxn];25 map
S[maxn];26 map
:: iterator it;27 void add(int x, int f, int y){28 S[y][bt[x]] = 1;29 for(int i = 0; i < G[x].size(); ++i){30 int to = G[x][i].first;31 if(to == f) continue;32 add(to, x, y);33 }34 }35 void dfs1(int x, int f){36 id[x] = x;37 int M = 0, ms = 0;38 for(int i = 0; i < G[x].size(); ++i){39 int to = G[x][i].first;40 if(to == f) continue;41 dfs1(to, x);42 if(sz[to] > M) M = sz[to], ms = to;43 }44 if(ms) id[x] = id[ms];45 for(int i = 0; i < G[x].size(); ++i){46 int to = G[x][i].first;47 if(to == f || to == ms) continue;48 add(to, x, id[x]);49 }50 it = S[id[x]].lower_bound(bt[x] - m);51 if(it != S[id[x]].end()) ans = max(ans, bt[x] - (*it).first);52 S[id[x]][bt[x]] = 1;53 }54 55 int main(){56 int T;57 scanf("%d", &T);58 while(T--){59 scanf("%d %d", &n, &m);60 for(int i = 1; i <= n; ++i) G[i].clear(), S[i].clear();61 for(int i = 1; i < n; ++i){62 int u, v, d;63 scanf("%d %d %d", &u, &v, &d);64 G[u].push_back(pii(v, d));65 G[v].push_back(pii(u, d));66 }67 ans = -1;68 dfs(1, 0);69 dfs1(1, 0);70 printf("%lld\n", ans);71 }72 return 0;73 }
Aguin

 

倒着并茶几

1 #include 
2 using namespace std; 3 const int maxn = 1e5 + 10; 4 int a[maxn], b[maxn], ans[maxn]; 5 int base[maxn][33], vis[maxn]; 6 7 int fa[maxn]; 8 int Find(int x){ 9 return fa[x] == x ? x : fa[x] = Find(fa[x]);10 }11 void Union(int x, int y){12 x = Find(x), y = Find(y);13 if(x == y) return;14 for(int i = 29; i >= 0; i--){15 if(!base[x][i]) continue;16 for(int j = 29; j >= 0; j--){17 if((1 << j) & base[x][i]){18 if(base[y][j]) base[x][i] ^= base[y][j];19 else {20 base[y][j] = base[x][i];21 break;22 }23 }24 }25 }26 fa[x] = y;27 }28 29 int main(){30 int N, M = 0;31 scanf("%d", &N);32 for(int i = 1; i <= N; ++i) fa[i] = i;33 for(int i = 1; i <= N; ++i) scanf("%d", a + i);34 for(int i = 1; i <= N; ++i) scanf("%d", b + i);35 for(int i = N; i >= 1; --i){36 int x = a[b[i]], y = 0;37 for(int j = 29; j >= 0; --j){38 if((1 << j) & x){39 base[b[i]][j] = x;40 break;41 }42 }43 vis[b[i]] = 1;44 if(vis[b[i] - 1]) Union(b[i] - 1, b[i]);45 if(vis[b[i] + 1]) Union(b[i] + 1, b[i]);46 x = Find(b[i]);47 for(int j = 29; j >= 0; --j){48 if((1 << j) & y) continue;49 y ^= base[x][j];50 }51 M = max(M, y);52 ans[i] = M;53 }54 for(int i = 1; i <= N; ++i) printf("%d\n", ans[i]);55 return 0;56 }
Aguin

 

 

转载于:https://www.cnblogs.com/Aguin/p/8893861.html

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